- # spread test, ksh style
- compound c;
- integer -a c.ar
- integer i z
- for (( i=0 ; i < 65536 ; i++ )) ; do
- (( z=i , (z%3==0) && c.ar[((z >> 4)&0x0F)*3][(z&0x0F)*7]++ ))
- done
- print -v c
- # EOF.
spread test
Posted by Anonymous on Tue 28th Jan 2020 08:26
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